Mathematics

ABCD is a trapezium with AB parallel to DC. Then the triangle similar to ΔAOB is:

  1. ΔACB

  2. ΔADB

  3. ΔCOB

  4. ΔCOD

ABCD is a trapezium with AB parallel to DC. Then the triangle similar to ΔAOB is: Similarity of Triangles, RSA Mathematics Solutions ICSE Class 10.

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Answer

Given,

Consider ΔAOB and ΔCOD

∠AOB = ∠COD [Vertically opposite angles are equal]

∠OBA = ∠ODC [Alternate angles are equal]

Therefore, by AA rule of similarity ΔAOB ~ ΔCOD.

Hence, option 4 is the correct option.

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