Add hexa-decimal numbers (1F5C) 16 and (AC2B) 16

Therefore, (1F5C) 16 + (AC2B) 16 = (CB87) 16 Explanation: 1. C + B = 12 + 11 = 23. As 23 is greater than 16 so 23 - 16 = 7. Hence, sum = 7 and carry over = 1. 2. 1 + 5 + 2 = 8. 3. F + C = 15 + 12 = 27. As 27 is greater than 16 so 27 - 16 = 11 or B. Hence, sum = B and carry over = 1. 4. 1 + 1 + A = 1 + 1 + 10 = 12 or C.

Add octal numbers (1546)₈ and (641)₈

View Answer Bookmark Now

Subtract octal number (2546)₈ from (5142)₈

View Answer Bookmark Now

Subtract hexa-decimal number (A68D)₁₆ from (D53F)₁₆

View Answer Bookmark Now

Subtract hexa-decimal number (ABCD)₁₆ from (EA9C)₁₆

View Answer Bookmark Now

Computer Science

Add hexa-decimal numbers (1F5C)₁₆ and (AC2B)₁₆

Number System

Related Questions

Add octal numbers (1546)₈ and (641)₈

Subtract octal number (2546)₈ from (5142)₈

Subtract hexa-decimal number (A68D)₁₆ from (D53F)₁₆

Subtract hexa-decimal number (ABCD)₁₆ from (EA9C)₁₆

Computer Science

Add hexa-decimal numbers (1F5C)16 and (AC2B)16

Number System

Related Questions

Add octal numbers (1546)8 and (641)8

Subtract octal number (2546)8 from (5142)8

Subtract hexa-decimal number (A68D)16 from (D53F)16

Subtract hexa-decimal number (ABCD)16 from (EA9C)16

Add hexa-decimal numbers (1F5C)₁₆ and (AC2B)₁₆

Add octal numbers (1546)₈ and (641)₈

Subtract octal number (2546)₈ from (5142)₈

Subtract hexa-decimal number (A68D)₁₆ from (D53F)₁₆

Subtract hexa-decimal number (ABCD)₁₆ from (EA9C)₁₆