Mathematics
a2 + 2a + 1 - b2 - x2 + 2bx is equal to :
(a + 1 - b + x) (a - 1 - b + x)
(a + 1 + b - x) (a + 1 - b + x)
(a - 1 + b - x) (a - 1 - b + x)
(a - 1 + bx) (a + 1 - bx)
Answer
a2 + 2a + 1 - b2 - x2 + 2bx
Using the formula
[∵ (x - y)2 = x2- 2xy + y2 ]
And
[∵ (x + y)2 = x2+ 2xy + y2 ]
= (a2 + 2a + 1) - (b2 + x2 - 2bx)
= (a + 1)2 - (b - x)2
Using the formula
[∵ (x2 - y2) = (x + y)(x - y)]
= ((a + 1) + (b - x))((a + 1) - (b - x))
= (a + 1 + b - x)(a + 1 - b + x)
Hence, option 2 is the correct option.