Physics
The circuit depicted in the figure is employed for studying Ohm's Law. Instead of using a standard resistor, a student opts for a glass tube filled with mercury (tube 1), connected to the circuit through two electrodes E1 & E2. He records the readings of the ammeter and voltmeter, thereby calculates the resistance. The student repeats the experiment by substituting tube 1 with tube 2, where the same amount of mercury fills the tube 2.

Neglecting internal resistance of the cell use (> or < or =) to compare
(a) the resistance in both the cases.
(b) the voltmeter readings in both the cases.
(c) the specific resistance in both the cases.
Current Electricity
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Answer
(a) As the resistance depends directly on length and inversely on area of the resistor and since here tube 2 is thicker and shorter than tube 1 thus, resistance of the tube 2 < resistance of the tube 1.
(b) The voltmeter reading for tube 1 is the same as the voltmeter reading for tube 2 because according to Ohm's law potential difference across a resistor depends only on the current applied not on the resistance of the resistor.
(c) As the specific resistance of a resistor is independent of its dimensions but depends only on the contained material and since here both tubes contain only mercury thus, the specific resistance in both the cases is the same.
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