Construct a rhombus ABCD in which AC = 5.6 cm and BD = 6.3 cm

Steps of construction:

1. Draw AC = 5.6 cm.

2. Draw the perpendicular bisector of AC which cuts AC at O.

3. From this perpendicular, cut OD and OB such that, OD = OB = $\dfrac{\text{BD}}{2} = \dfrac{6.3}{2} = 3.1$ cm.

4. Join AB, BC, CD and DA.

Hence, ABCD is the required rhombus.