Find the seventh term from the end of the series : √2, 2, 2√2, ........, 32.

Since, . So, the above sequence is a G.P. with r = . Let there be n terms. m th term from end is (n - m + 1) th term from starting. So, 7 th term from end is (10 - 7 + 1) = 4 th term from starting. a 4 = ar 3 = = = 4. Hence, 7 th term from end is 4.