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The following figure shows a circle with centre O and diameter PQ. Point R lies on the circumference of the circle such that PR = QR and PR = 4 cm.

The following figure shows a circle with centre O and diameter PQ. Point R lies on the circumference of the circle such that PR = QR and PR = 4 cm. Circles, Concise Mathematics Solutions ICSE Class 8.

Calculate the radius of the given circle and state its value correct to two decimal places.

Circles

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Answer

Given, PQ is diameter of the circle.

PR = QR and PR = 4 cm

⇒ QR = 4 cm

As we know that,

Angle in a semi-circe is a right angle.

⇒ ∠PRQ = 90°

Triangle PQR is a right triangle with hypotenuse PQ. Using Pythagoras theorem,

⇒ PQ2 = PR2 + RQ2

⇒ PQ2 = 42 + 42

⇒ PQ2 = 16 + 16

⇒ PQ2 = 32

⇒ PQ = 32\sqrt{32} = 5.66 cm

Radius (OP) = 12×PQ=12×5.66\dfrac{1}{2} \times PQ = \dfrac{1}{2} \times 5.66

= 2.83 cm.

Hence, the radius of the given circle = 2.83 cm.

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