Mathematics
In rhombus ABCD :
(i) if ∠A = 74°, find ∠B and ∠C.
(ii) if AD = 7.5 cm, find BC and CD.
Answer
(i) In a rhombus, opposite angles are equal, and the diagonals bisect each other at 90°. Additionally, consecutive angles are supplementary.

⇒ ∠A + ∠B = 180°
It is given that ∠A = 74°.
⇒ 74° + ∠B = 180°
⇒ ∠B = 180° - 74°
⇒ ∠B = 106°
Since opposite angles are equal, we have:
∠A = ∠C and ∠B = ∠D
Hence, ∠B = 106° and ∠C = 74°.
(ii) In a rhombus, all sides are equal.
Therefore, AB = BC = CD = DA = 7.5 cm.
Hence, the length of sides BC = CD = 7.5cm.
Related Questions
In parallelogram ABCD, ∠A = 3 times ∠B. Find all the angles of the parallelogram. In the same parallelogram, if AB = 5x - 7 and CD = 3x + 1, find the length of CD.
In parallelogram PQRS, ∠Q = (4x - 5)° and ∠S = (3x + 10)°. Calculate: ∠Q and ∠R.
In square PQRS :
(i) if PQ = 3x - 7 and QR = x + 3, find PS.
(ii) if PR = 5x and QS = 9x — 8. Find QS.
ABCD is a rectangle. If ∠BPC = 124°, calculate :
(i) ∠BAP
(ii) ∠ADP.
