Mathematics
In the given figure, AF // BE and PQ // RS, FC and ED are perpendiculars to RS. The area of parallelogram ABEF is equal to :
rect. CDEF
quad. CBEF
2 × △ACF
2 × △EBD
Theorems on Area
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Answer
We know that,
Parallelogram on equal bases and between the same parallel are equal in area.
A rectangle is also a parallelogram.
From figure,
Parallelogram ABEF and rectangle CDEF lie on same base FE and between same parallel lines PQ and RS.
∴ Area of parallelogram ABEF = Area of rectangle CDEF.
Hence, Option 1 is the correct option.
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