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In the given figure, BD : DC = 3 : 5, then area of △ ABD : area of △ ACD is :

In the given figure, BD : DC = 3 : 5, then area of △ ABD : area of △ ACD is : Area Theorems, Concise Mathematics Solutions ICSE Class 9.
  1. 5 : 3

  2. 3 : 5

  3. 25 : 9

  4. 9 : 25

Theorems on Area

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Answer

In the given figure,

△ ABD and △ ACD has same vertex A and bases along the same straight line BC.

Area of △ ABDArea of △ ACD=BDDC=35\dfrac{\text{Area of △ ABD}}{\text{Area of △ ACD}} = \dfrac{BD}{DC} = \dfrac{3}{5}

∴ area of △ ABD : area of △ ACD = 3 : 5.

Hence, Option 2 is the correct option.

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