If M is the mean of six natural numbers x1, x2, x3, x4, x5 and x6. Show that : (x1 - M) + (x2 - M) + (x3 - M) + (x4 - M) + (x5 - M) + (x6 - M) = 0

Given, M is the mean of six natural numbers x1, x2, x3, x4, x5 and x6. = M ⇒ x1 + x2 + x3 + x4 + x5 + x6 = 6M ⇒ x1 + x2 + x3 + x4 + x5 + x6 = M + M + M + M + M + M ⇒ (x1 - M) + (x2 - M) + (x3 - M) + (x4 - M) + (x5 - M) + (x6 - M) = 0 Hence, proved that (x1 - M) + (x2 - M) + (x3 - M) + (x4 - M) + (x5 - M) + (x6 - M) = 0.