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Mathematics

The mean of the following distribution is 50 and the frequency of the class-interval 20-40 is m, find the value of m.

Class-intervalFrequency
0-2017
20-40m
40-6032
60-8024
80-10019

Statistics

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Answer

Class-intervalClass-mark (x)Frequency (f)fx
0-201017170
20-4030m30m
40-6050321600
60-8070241680
80-10090191710
TotalΣf = 92 + mΣfx = 5160 + 30m

Given,

Mean = 50

5160+30m92+m=50\therefore \dfrac{5160 + 30m}{92 + m} = 50

⇒ 5160 + 30m = 50(92 + m)

⇒ 5160 + 30m = 4600 + 50m

⇒ 50m - 30m = 5160 - 4600

⇒ 20m = 560

⇒ m = 56020\dfrac{560}{20} = 28.

Hence, m = 28.

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