(sec θ - cos θ)2 - (sec θ + cos θ)2 is equal to :
4
2
-2
-4
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If a = tan θ and b = sec θ, the relation between a and b is :
a × b = 1
a2 - b2 = 1
b2 - a2 = 1
a2 + b2 = 1
(cot A - cot B)2 + (1 + cot A cot B)2 is equal to :
sec2 A - cos2 A
sec2 A - cosec2 A
(1 + tan A)2 - (1 - cot A)2
cosec2 A . cosec2 B
Prove that:
(sec A - tan A)2 (1 + sin A) = (1 - sin A)