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The base of a triangular field is three times its height. If the cost of cultivating the field at ₹ 36.72 per 100 m2 is ₹ 49,572; find its base and height.

Mensuration

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Answer

Given:

Cost of cultivating the field = ₹ 36.72 per 100 m2

Total cost = ₹ 49,572

Total cost = Area x Cost of cultivating per 100 m2

Area = Total costCost of cultivating\dfrac{\text{Total cost}}{\text{Cost of cultivating}}

=49,572×10036.72=49,572×10,0003672=1,35,000 m2= \dfrac{49,572 \times 100}{36.72}\\[1em] = \dfrac{49,572 \times 10,000}{3672}\\[1em] = 1,35,000 \text{ m}^2

Let the height of the triangle be h.

Since the base of the field is three times its height, we have:

Base = 3h

The base of a triangular field is three times its height. If the cost of cultivating the field at ₹ 36.72 per 100 m2 is ₹ 49,572; find its base and height. Area and Perimeter of Plane Figures, Concise Mathematics Solutions ICSE Class 9.

Area = 12\dfrac{1}{2} x base x height

1,35,000=12×3h×h1,35,000=32×h2h2=1,35,000×23h2=2,70,0003h2=90,000h=90,000h=300⇒ 1,35,000 = \dfrac{1}{2} \times 3h \times h\\[1em] ⇒ 1,35,000 = \dfrac{3}{2} \times h^2\\[1em] ⇒ h^2 = \dfrac{1,35,000 \times 2}{3}\\[1em] ⇒ h^2 = \dfrac{2,70,000}{3}\\[1em] ⇒ h^2 = 90,000\\[1em] ⇒ h = \sqrt{90,000}\\[1em] ⇒ h = 300

Thus, the height of the triangle is 300 m.

Base = 3 x height = 3 x 300 m = 900 m

Hence, the height is 300 m and the base is 900m.

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