The lengths of the sides of a triangle are in the ratio 4 : 5 : 3 and its perimeter is 96 cm. Find its area.

Given: Perimeter of the triangle = 96 cm The lengths of the sides of a triangle are in the ratio 4 : 5 : 3. Let the length of the sides of the triangle be 4a, 5a and 3a. ∵ Perimeter of triangle = sum of sides of the triangle. ⇒ 4a + 5a + 3a = 96 cm ⇒ 12a = 96 cm ⇒ a = cm ⇒ a = 8 cm So, the lengths of the sides are 4a, 5a and 3a. = 4 x 8, 5 x 8 and 3 x 8 = 32, 40 and 24 Let a = 32 m, b = 40 m and c = 24 m. ∵ Area of triangle = = cm 2 = cm 2 = cm 2 = 384 cm 2 Hence, the area of the triangle is 384 cm 2 .

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Mathematics

The lengths of the sides of a triangle are in the ratio 4 : 5 : 3 and its perimeter is 96 cm. Find its area.

Area Trapezium Polygon

Related Questions

The area of an equilateral triangle is numerically equal to its perimeter. Find its perimeter correct to 2 decimal places.

A field is in the shape of a quadrilateral ABCD in which side AB = 18 m, side AD = 24 m, side BC = 40 m, DC = 50 m and angle A = 90°. Find the area of the field.

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