Calculate the area of the figure given below which is not drawn to scale.

Area of figure ABCEF = Area of trapezium ABCF \+ Area of triangle CEF Area of triangle CEF = x b x h = x CF x DE = x 25 x 12 m 2 = 25 x 6 m 2 = 150 m 2 In triangle BGC, Base 2 \+ Height 2 = Hypotenuse 2 ⇒ CG 2 \+ BG 2 = CB 2 Let `h` be the length of BG. ⇒ 10 2 \+ h 2 = 26 2 (∵CG = CF \- GF = CF \- BA = 25 \- 15 = 10) ⇒ 100 \+ h 2 = 676 ⇒ h 2 = 676 \- 100 ⇒ h 2 = 576 ⇒ h = ⇒ h = 24 cm Area of trapezium = (sum of parallel sides) x distance between the parallel sides = (AB \+ CF) x BG = (15 \+ 25) x 24 m 2 = x 40 x 24 m 2 = 20 x 24 m 2 = 480 m 2 So, total area of figure ABCEF = 150 \+ 480 m 2 = 630 m 2 Hence, the area is 630 m 2 .

The perimeter of a rhombus is 46 cm. If the height of the rhombus is 8 cm; find its area.

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The given figure shows the cross-section of a concrete structure. Calculate the area of cross-section if AB = 1.8 m, CD = 0.6 m, DE = 0.8 m, EF = 0.3 m and AF = 1.2 m.

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The following diagram shows a pentagonal field ABCDE in which the lengths of AF, FG, GH and HD are 50 m, 40 m, 15 m and 25 m respectively; and the lengths of perpendiculars BF, CH and EG are 50 m, 25 m and 60 m respectively. Determine the area of the field.

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Mathematics

Calculate the area of the figure given below which is not drawn to scale.

Mensuration

Related Questions

The perimeter of a rhombus is 46 cm. If the height of the rhombus is 8 cm; find its area.

The given figure shows the cross-section of a concrete structure. Calculate the area of cross-section if AB = 1.8 m, CD = 0.6 m, DE = 0.8 m, EF = 0.3 m and AF = 1.2 m.

The following diagram shows a pentagonal field ABCDE in which the lengths of AF, FG, GH and HD are 50 m, 40 m, 15 m and 25 m respectively; and the lengths of perpendiculars BF, CH and EG are 50 m, 25 m and 60 m respectively. Determine the area of the field.