Mathematics
Related Questions
In the given figure, ∠ABC = 66°, ∠DAC = 38°. CE is perpendicular to AB and AD is perpendicular to BC. Prove that: CP > AP.

In a △ABC, AB = AC and ∠B = 50°. Then ∠A =
50°
80°
100°
105°
In the adjoining figure, ∠ABC = 90°, ∠BCA = 50° and BD ⊥ AC. Then ∠ABD =

30°
40°
50°
60°
In the adjoining figure, AB = AC and BD = CD. Then, ∠ADC =

60°
75°
90°
100°