Construct a rhombus ABCD in which AC = 5.6 cm and BD = 6.3 cm

Steps of construction: 1. Draw AC = 5.6 cm. 2. Draw the perpendicular bisector of AC which cuts AC at O. 3. From this perpendicular, cut OD and OB such that, OD = OB = cm. 4. Join AB, BC, CD and DA. Hence, ABCD is the required rhombus.

Construct a square ABCD in which diagonal AC = 9 cm.

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Construct a rhombus ABCD in which each side = 6 cm and ∠B = 45°.

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Construct a rectangle ABCD with diagonal AC = 6.6 cm, side BC = 5.2 cm and ∠B = 90°.

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The following diagram shows two parallelograms ABCD and BEFG.
Prove that :
Area of // gm ABCD = Area of // gm BEFG.

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Mathematics

Construct a rhombus ABCD in which AC = 5.6 cm and BD = 6.3 cm

Rectilinear Figures

Related Questions

Construct a square ABCD in which diagonal AC = 9 cm.

Construct a rhombus ABCD in which each side = 6 cm and ∠B = 45°.

Construct a rectangle ABCD with diagonal AC = 6.6 cm, side BC = 5.2 cm and ∠B = 90°.

The following diagram shows two parallelograms ABCD and BEFG.
Prove that :
Area of // gm ABCD = Area of // gm BEFG.

Mathematics

Construct a rhombus ABCD in which AC = 5.6 cm and BD = 6.3 cm

Rectilinear Figures

Related Questions

Construct a square ABCD in which diagonal AC = 9 cm.

Construct a rhombus ABCD in which each side = 6 cm and ∠B = 45°.

Construct a rectangle ABCD with diagonal AC = 6.6 cm, side BC = 5.2 cm and ∠B = 90°.

The following diagram shows two parallelograms ABCD and BEFG.Prove that :Area of // gm ABCD = Area of // gm BEFG.

The following diagram shows two parallelograms ABCD and BEFG.
Prove that :
Area of // gm ABCD = Area of // gm BEFG.