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10 g of ice at 0° C absorbs 5460 J of heat energy to melt and change to water at 50° C. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J kg-1 K-1.
Calorimetry
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Answer
Given,
Mass (m) = 10 g
Heat energy absorbed (Q) = 5460 J
Specific heat capacity of water = 4200 J kg-1 K-1 = 4.2 J g-1 K-1
Specific latent heat of fusion of ice (L) = ?
(i) Heat energy required to melt the ice at 0° C to water at 0° C (Q1) = m x L
Substituting the values in the formula we get,
(ii) Heat energy required to raise temperature from 0° C to 50° C = m x c x rise in temperature
Substituting the values in the formula we get,
From relation,
Hence, Specific latent heat of fusion of ice = 336 J g-1
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