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10 mL of a solution of NaOH is found to be completely neutralized by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralize it will be
- 4 mL
- 8 mL
- 12 mL
- 16 mL
Acids Bases Salts
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Answer
16 mL
Reason — When 10 mL of a solution of NaOH is found to be completely neutralized by 8 mL of a given solution of HCl, then is we take 20 mL of the same solution of NaOH i.e, double the initial solution of NaOH so double amount of HCl will be required i.e. 16 mL.
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