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Chemistry

10g of magnesium carbonate reacts completely with excess dilute hydrochloric acid. What volume of carbon dioxide is formed at room temperature and pressure? [Mg=24, C=12, O=16] The equation for the reaction is:

MgCO3 + 2HCl ⟶ MgCl2 + H2O + CO2

  1. 2.8 dm3
  2. 2.6 dm3
  3. 2.2 dm3
  4. 2.4 dm3

Mole Concept

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Answer

2.6 dm3

ReasonMgCO31mol+HCl1molMgCl21mol+H2O+CO2\underset{1\text{mol}}{\text{MgCO}3} + \underset{1\text{mol}}{\text{HCl}} \longrightarrow \underset{1\text{mol}}{\text{MgCl}2} + \text{H}2\text{O} + \text{CO}2

1 mole of MgCO3 gives 1 mole of CO2

Molar Mass of MgCO3

MgCO3 = 1 x 24 + 1 X 12 + 3 X 16 = 84 g/mol

∴ No. of moles of MgCO3 in 10g

Moles of MgCO3 = 1084\dfrac{10}{84} = 0.119 mol

From the reaction, 1 mole of MgCO2 gives 1 mole of CO2,

∴ Moles of CO2 = 0.119mol

Volume of CO2 at RTP,

= 0.119 X 22.4 = 2.6 dm3

∴ volume of carbon dioxide at RTP is 2.6 dm3

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