₹ 16,000 is invested at 5% compound interest compounded per annum. Use the table, given below, to find the amount in 4 years.

Year	Initial amount (₹)	Interest (₹)	Final amount (₹)
1st	16000	800	16800
2nd	----	----	------
3rd	----	----	-----
4th	----	----	----
5th	----	----	----

For 2nd year :

P = ₹ 16800

R = 5%

T = 1 year

I = $\dfrac{P \times R \times T}{100} = \dfrac{16800 \times 5 \times 1}{100}$ = ₹ 840.

A = P + I = ₹ 16800 + ₹ 840 = ₹ 17640.

For 3rd year :

P = ₹ 17640

R = 5%

T = 1 year

I = $\dfrac{P \times R \times T}{100} = \dfrac{17640 \times 5 \times 1}{100}$ = ₹ 882.

A = P + I = ₹ 17640 + ₹ 882 = ₹ 18522.

For 4th year :

P = ₹ 18522

R = 5%

T = 1 year

I = $\dfrac{P \times R \times T}{100} = \dfrac{18522 \times 5 \times 1}{100}$ = ₹ 926.10.

A = P + I = ₹ 18522 + ₹ 926.10 = ₹ 19448.10

For 5th year :

P = ₹ 19488.10

R = 5%

T = 1 year

I = $\dfrac{P \times R \times T}{100} = \dfrac{19448.10 \times 5 \times 1}{100}$ = ₹ 972.405.

A = P + I = ₹ 19448.10 + ₹ 972.405 = ₹ 20420.505

Hence, amount in 4 years = ₹ 19448.10