Mathematics
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears
(i) a two-digit number
(ii) a perfect square number
(iii) a number divisible by 5
(iv) a prime number less than 30.
Probability
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Answer
A disc is drawn at random from the box means that all the outcomes are equally likely.
Sample space = {1, 2, 3, ….., 90}, which has 90 equally likely outcomes.
(i) Let E1 be the event of drawing a disc with two digit number.
E1 = {10, 11, 12, 13, ……, 90}.
∴ The number of favourable outcomes to the event E1 = 81.
Hence, the probability of drawing a disc with two digit number is
(ii) Let E2 be the event of drawing a disc with perfect square number.
E2 = {1, 4, 9, 16, 25, 36, 49, 64, 81}.
∴ The number of favourable outcomes to the event E2 = 9.
Hence, the probability of drawing a disc with perfect square number is .
(iii) Let E3 be the event of drawing a disc with number divisible by 5.
E3 = {5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90}.
∴ The number of favourable outcomes to the event E3 = 18.
Hence, the probability of drawing a disc with number that is divisible by 5 is .
(iv) Let E4 be the event of drawing a disc with prime number less than 30.
E4 = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29}.
∴ The number of favourable outcomes to the event E4 = 10.
Hence, the probability of drawing a disc with prime number less than 30 is .
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