A carton consist of 100 shirts of which 88 are good, 8 have minor defects and 4 have major defects. Peter, a trader, will only accept the shirts which are good, but Salim, another trader, will only reject the shirts which have major defects. One shirt is drawn at random from the carton. What is the probability that

(i) it is acceptable to Peter?

(ii) it is acceptable to Salim?

(i) No. of good shirts = 88
    Total no. of shirts = 100.

Let E₁ be the event of choosing a good shirt, then number of favourable outcomes to E₁ = 88

$P(E$1) = \dfrac{\text{No. of favourable outcomes to } E1}{\text{Total no. of possible outcomes}} = \dfrac{88}{100} = \dfrac{22}{25}.

Hence, the probability that shirt is acceptable to Peter is $\dfrac{22}{25}$.

(ii) No. of good and minor defective shirts = 88 + 8 = 96
    Total no. of shirts = 100.

Let E₂ be the event of choosing a good or minor defective shirt, then number of favourable outcomes to E₂ = 96

$P(E$2) = \dfrac{\text{No. of favourable outcomes to } E2}{\text{Total no. of possible outcomes}} = \dfrac{96}{100} = \dfrac{24}{25}.

Hence, the probability that shirt is acceptable to Salim is $\dfrac{24}{25}$.