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Mathematics

A computer mechanic in Delhi charges repairing cost from five different persons A, B, C, D and E with certain discounts.

The repairing costs and the corresponding discounts are as given below:

Name of the personsABCDE
Repairing cost (in ₹)5,5006,2504,8007,2003,500
Discount %3040302040

If the rate of GST is 18%, find the total money (including GST) received by the mechanic.

GST

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Answer

We know that, Discounted value % = 100% - Discount %.

Name of the personsRepairing cost (in ₹)Discount %Discounted value %Discounted value
A5,500307070100\dfrac{70}{100} x 5,500 = 3850
B6,250406060100\dfrac{60}{100} x 6,250 = 3750
C4,800307070100\dfrac{70}{100} x 4,800 = 3360
D7,200208080100\dfrac{80}{100} x 7,200 = 5760
E3,500406060100\dfrac{60}{100} x 3,500 = 2100
Total18820

GST = 18%.

GST = 18100×18820\dfrac{18}{100} \times 18820 = ₹3387.60

Total money = ₹18820 + ₹3387.60 = ₹22207.60

Hence, the total money received by mechanic = ₹22207.60

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