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Mathematics

A dealer in Mumbai supplied some identical items at the following prices to a dealer in Delhi. Find the total amount of bill.

Rate per item (in ₹)Quantity (no. of items)Discount %SGST %
180109
26020209
310309
17520309

GST

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Answer

Discounted% = 100% - Discount%.

IGST% = 2SGST%

Quantity (No.of items)Rate per item (in ₹)Total valueDiscount%Discounted valueIGST%IGST (in ₹)Total value (Discounted Value + IGST)
10180180018001818100×1800\dfrac{18}{100} \times 1800 = 3242124
2026052002080100×5200\dfrac{80}{100} \times 5200 = 41601818100×4160\dfrac{18}{100} \times 4160 = 748.804908.80
30310930093001818100×9300\dfrac{18}{100} \times 9300 = 167410974
2017535003070100×3500=2450\dfrac{70}{100} \times 3500 = 24501818100×2450\dfrac{18}{100} \times 2450 = 4412891
Total20897.80

Hence, the amount of bill = ₹ 20897.80

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