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Chemistry

A fixed mass of a gas has a volume of 750 cc at -23°C and 800 mm pressure. Calculate the pressure for which it's volume will be 720 cc. The temperature being -3°C.

Gas Laws

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Answer

Initial ConditionsFinal Conditions
V1 = Initial volume of the gas = 750 ccV2 = Final volume of the gas = 720 cc
T1 = Initial temperature of the gas = -23°C = -23 + 273 = 250 KT2 = Final temperature of the gas = -3°C = -3 + 273 = 270 K
P1 = Initial pressure of the gas = 800 mmP2 = Final pressure of the gas = ?

By Gas Law:

P1×V1T1=P2×V2T2\dfrac{\text{P}1\times\text{V}1}{\text{T}1} = \dfrac{\text{P}2\times\text{V}2}{\text{T}2}

Substituting the values :

800×750250=P2×720270P2=800×750×270250×720P2=900 mm\dfrac{800 \times 750}{250} = \dfrac{\text{P}2 \times 720}{270} \\[1em] \text{P}2 = \dfrac{800 \times 750 \times 270}{250 \times 720} \\[1em] \text{P}_2 = 900 \text{ mm}

Therefore, final pressure of the gas = 900 mm

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