Chemistry
A gas cylinder contains 12 x 1024 molecules of oxygen gas.
If Avogadro's number is 6 x 1023; Calculate:
(i) the mass of oxygen present in the cylinder.
(ii) the volume of oxygen at S.T.P. present in the cylinder. [O=16]
Mole Concept
ICSE 2016
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Answer
Gram molecular mass of oxygen = 32 g = 1 mole and contains 6 x 1023 molecules i.e., 6 x 1023 molecules weigh 32 g
∴ 12 x 1024 molecules will weigh = x 12 x 1024 = 640 g
(ii) 6 x 1023 molecules occupy 22.4 lit. of vol.
∴ 12 x 1024 molecules will occupy = x 12 x 1024 = 448 lit.
Hence, mass of O2 present in the cylinder = 640 g and volume of O2 at S.T.P. present in the cylinder = 448 lit.
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