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A hockey ball of mass 200 g travelling at 10 ms-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 ms-1. Calculate the magnitude of change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Laws of Motion

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Answer

Given,

Mass (m) = 200 g

Initial velocity (u) = 10 ms-1

Final velocity (v) = -5 ms-1

Initial momentum of the ball = mu = 200 × 10 = 2000 gms-1

Final momentum of the ball = mv = 200 × -5 = -1000 gms-1

∴ The change in momentum (mv - mu) = -1000 - 2000 = -3000 gms-1

Convert gms-1 to kgms-1 :

1000 gms-1 = 1 kgms-1

So, 3000 gms-1 = 30001000\dfrac{3000}{1000} = -3 kgms-1

Hence, momentum of the ball reduces by 3 kgms-1 after being struck by the hockey stick.

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