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Mathematics

A man invests ₹10400 in 6% shares at ₹104 and ₹11440 in 10.4% shares at ₹143. How much income would he get in all? (Assume face value of ₹100)

Shares & Dividends

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Answer

First Investment:

Total Investment = ₹10400

Market Value per share = ₹104

∴ No. of shares

=Total InvestmentMV per share=10400104=100= \dfrac{\text{Total Investment}}{\text{MV per share}} \\[0.7em] = \dfrac{10400}{104} \\[0.5em] = \bold{100}

Rate of Dividend = 6%

As Nominal value is not given, let's assume it to be ₹100 per share

Annual Dividend = No. of shares x Rate of Dividend x Nominal Value per share

=100×6100×100=600= 100 \times \dfrac{6}{100} \times 100 \\[0.5em] = \bold{₹600}

Second Investment:

Total Investment = ₹11440

Market Value per share = ₹143

∴ No. of shares

=Total InvestmentMV per share=11440143=80= \dfrac{\text{Total Investment}}{\text{MV per share}} \\[0.7em] = \dfrac{11440}{143} \\[0.5em] = \bold{80}

Rate of Dividend = 10.4%

As Nominal value is not given, let's assume it to be ₹100 per share

Annual Dividend = No. of shares x Rate of Dividend x Nominal Value per share

=80×10.4100×100=832= 80 \times \dfrac{10.4}{100} \times 100 \\[0.5em] = \bold{₹832}

Total Income = Income from first investment + Income from second investment
= ₹600 + ₹832
= ₹1432

∴ Total Income = ₹1432

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