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Mathematics

A man invests ₹3072 for two years at compound interest. After one year the money amounts to ₹3264. Find the rate of interest and the amount due at the end of 2nd year.

Compound Interest

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Answer

Let the rate of interest be r% per annum.

Given, ₹3072 amounts to ₹3264 in one year.

∴ Compound interest = Final amount - Principal = ₹3264 - ₹3072 = ₹192.

192=3072×r×1100r=192003072r=6.25%.\therefore 192 = \dfrac{3072 \times r \times 1}{100} \\[1em] \Rightarrow r = \dfrac{19200}{3072} \\[1em] \Rightarrow r = 6.25\%.

Principal for second year = ₹3264.

C.I.= 3264×6.25×1100=20400100\dfrac{3264 \times 6.25 \times 1}{100} = \dfrac{20400}{100} = ₹204.

Amount after second year = ₹3264 + ₹204 = ₹3468.

Hence, the rate of interest = 6.25% and the amount after second year = ₹3468.

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