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Mathematics

A manufacturer estimates that his machine depreciates by 15% of its value at the beginning of the year. Find the original value of machine, if it depreciates by ₹ 5355 during the second year.

Compound Interest

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Answer

Let original value of machine be ₹ x.

For first year :

P = ₹ x

R (of depreciation) = 15%

T = 1 year

Depreciation = P×R×T100=x×15×1100=3x20\dfrac{P \times R \times T}{100} = \dfrac{x \times 15 \times 1}{100} = \dfrac{3x}{20}.

New value = P - Depreciation = x3x20=17x20x - \dfrac{3x}{20} = \dfrac{17x}{20}.

For second year :

P = ₹ 17x20\dfrac{17x}{20}

R (of depreciation) = 15%

T = 1 year

Depreciation = P×R×T100=17x20×15×1100=51x400\dfrac{P \times R \times T}{100} = \dfrac{\dfrac{17x}{20} \times 15 \times 1}{100} = \dfrac{51x}{400}.

Given,

Depreciation in second year = ₹ 5355

51x400=5355x=5355×40051x=105×400=42000.\therefore \dfrac{51x}{400} = 5355 \\[1em] \Rightarrow x = \dfrac{5355 \times 400}{51} \\[1em] \Rightarrow x = 105 \times 400 = 42000.

Hence, original value of machine = ₹ 42000.

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