Physics
A mechanic can open a nut by applying a force of 150 N while using a lever handle of length 40 cm. How long a handle is required if he wants to open it by applying a force of only 50 N ?
Force
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Answer
Given,
F1 = 150 N
I1 = 40 cm = 0.4 m
F2 = 50 N
I2 = ?
∵ F1 x I1 = F2 x I2
150 x 0.4 = 50 x I2
I2 =
I2 = 1.2 m = 120 cm
∴ Length of handle required for 50 N force = 120 cm.
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