Chemistry
An organic compound, whose vapour density is 45, has the following percentage composition,
H = 2.22%, O = 71.19% and remaining carbon.
Calculate :
(a) its empirical formula,
(b) its molecular formula.
Mole Concept
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Answer
| Element | % composition | At. wt. | Relative no. of atoms | Simplest ratio |
|---|---|---|---|---|
| Hydrogen | 2.22 | 1 | = 2.22 | = 1 |
| Oxygen | 71.19 | 16 | = 4.44 | = 2 |
| Carbon | 26.59 | 12 | = 2.21 | = 1 |
Simplest ratio of whole numbers = H : O : C = 1 : 2 : 1
Hence, empirical formula is CHO2
Empirical formula weight = 12 + 1 + (2 x 16) = 13 + 32 = 45
V.D. = 45
Molecular weight = 2 x V.D. = 2 x 45 = 90
So, molecular formula = 2(CHO2) = C2H2O4
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