KnowledgeBoat Logo
|

Mathematics

As observed from the top of a 80 m tall lighthouse, the angles of depression of two ships, on the same side of a light house in a horizontal line with its base, are 30° and 40° respectively. Find the distance between two ships. Give your answer correct to nearest metre.

Heights & Distances

2 Likes

Answer

As, alternate angles are equal.

∴ ∠BCA = ∠EBC = 30° and ∠BDA = ∠EBD = 40°.

Let AB be the lighthouse.

As observed from the top of a 80 m tall lighthouse, the angles of depression of two ships, on the same side of a light house in a horizontal line with its base, are 30° and 40° respectively. Find the distance between two ships. Give your answer correct to nearest metre. Heights and Distances, Concise Mathematics Solutions ICSE Class 10.

In △ABC,

tan 30°=PerpendicularBase13=ABACAC=3ABAC=803=138.56 m.\text{tan 30°} = \dfrac{\text{Perpendicular}}{\text{Base}} \\[1em] \Rightarrow \dfrac{1}{\sqrt{3}} = \dfrac{AB}{AC} \\[1em] \Rightarrow AC = \sqrt{3}AB \\[1em] \Rightarrow AC = 80\sqrt{3} = 138.56 \text{ m}.

In △ABD,

tan 40°=PerpendicularBase0.84=ABADAD=800.84AD=95.24 m.\text{tan 40°} = \dfrac{\text{Perpendicular}}{\text{Base}} \\[1em] \Rightarrow 0.84 = \dfrac{AB}{AD} \\[1em] \Rightarrow AD = \dfrac{80}{0.84} \\[1em] \Rightarrow AD = 95.24 \text{ m}.

From figure,

CD = AC - AD = 138.56 - 95.24 = 43.32 ≈ 43 m.

Hence, distance between two ships = 43 m.

Answered By

1 Like


Related Questions