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Mathematics

Assertion (A) : The simple interest on a certain sum is 916\dfrac{9}{16} of the principal. If the number representing the rate of interest in percent and the time in year are equal then the time for which the principle is lent out is 7127\dfrac{1}{2} years.

Reason (R) : In simple interest,

Time = S.I.×100Principal×Rate\dfrac{\text{S.I.} \times 100}{\text{\text{Principal}} \times \text{Rate}}.

  1. Both A and R are correct, and R is the correct explanation for A.

  2. Both A and R are correct, and R is not the correct explanation for A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Simple Interest

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Answer

Let the principal be ₹ P.

S.I. = 916\dfrac{9}{16} x P

Rate of interest = a%

Time = a years

By formula,

S.I. = P×R×T100\dfrac{P \times R \times T}{100}

Substituting values we get :

916P=P×a×a100916P=P×a×a100916=a×a100916=a2100a2=9×10016a2=90016a=90016a=304a=152a=712\Rightarrow \dfrac{9}{16}P = \dfrac{P \times a \times a}{100}\\[1em] \Rightarrow \dfrac{9}{16} \cancel{P} = \dfrac{\cancel{P} \times a \times a}{100}\\[1em] \Rightarrow \dfrac{9}{16} = \dfrac{a \times a}{100}\\[1em] \Rightarrow \dfrac{9}{16} = \dfrac{a^2}{100}\\[1em] \Rightarrow a^2 = \dfrac{9 \times 100}{16}\\[1em] \Rightarrow a^2 = \dfrac{900}{16}\\[1em] \Rightarrow a = \sqrt{\dfrac{900}{16}}\\[1em] \Rightarrow a = \dfrac{30}{4}\\[1em] \Rightarrow a = \dfrac{15}{2}\\[1em] \Rightarrow a = 7\dfrac{1}{2}

Time = 7127\dfrac{1}{2} years.

So, assertion (A) is true.

By formula;

S.I.=P×R×T100T=S.I.×100P×RTime =Simple Interest×100Principal×Rate\Rightarrow S.I. = \dfrac{P \times R \times T}{100} \\[1em] \Rightarrow T = \dfrac{\text{S.I.} \times 100}{P \times R} \\[1em] \Rightarrow \text{Time } = \dfrac{\text{Simple Interest} \times 100}{\text{Principal} \times \text{Rate}}

So, reason (R) is true and reason (R) clearly explains assertion (A).

Hence, option 1 is the correct option.

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