Assuming temperature remaining constant calculate the pressure of the gas :

The pressure of a gas having volume 1500 cm³ originally occupying 750 cc. at 5 atms. pressure.

V₁ = Initial volume of the gas = 750 cc
P₁ = Initial pressure of the gas = 5 atms.

V₂ (Final volume) = 1500 cc
P₂ = Final pressure of the gas = ?

By Boyle's Law:

$\text{P}$1 \text{V}1 = \text{P}2 \text{V}2

Substituting the values :

$5 \times 750 = \text{P}$2 \times 1500 \\[0.5em] \text{P}2 = \dfrac{5 \times 750}{1500} \\[0.5em] \text{P}_2 = 2.5 \text{ atms }

Therefore, final pressure of the gas = 2.5 atms.