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Chemistry

Calculate percentage of platinum in [(NH4)2 PtCl6]. Ammonium chloride platinate in nearest whole number.

Stoichiometry

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Answer

The relative molecular mass of (NH4)2 PtCl6
     = 2(14 + 4 x 1) + 195 + 6 x 35.5
     = 36 + 195 + 213
     = 444 amu

Wt. of Pt in [(NH4)2 PtCl6] = 195 g

∴ Percentage of platinum in (NH4)2PtCl6 is

    = 195444\dfrac{195}{444} x 100

    = 43.91 %

∴ Rounding to the nearest whole number, the percentage of platinum in ammonium chloride platinate (NH4)2 PtCl6 is 44%.

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