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Mathematics

Calculate the difference between the compound interest and the simple interest on ₹ 7,500 in two years and at 8% per annum.

Simple Interest

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Answer

P = ₹ 7,500

R = 8%

T = 2 years

For simple interest

Interest=(P×R×T100)=(7,500×8×2100)=(1,20,000100)=1,200\text{Interest} = \Big(\dfrac{P \times R \times T}{100}\Big)\\[1em] = \Big(\dfrac{7,500 \times 8 \times 2}{100}\Big)\\[1em] = \Big(\dfrac{1,20,000}{100}\Big)\\[1em] = ₹ 1,200

For compound interest

A=P[1+R100]n=7,500[1+8100]2=7,500[1+225]2=7,500[2525+225]2=7,500[(25+2)25]2=7,500[2725]2=7,500[729625]2=[54,67,500625]2=8,748\text{A} = P\Big[1 + \dfrac{R}{100}\Big]^n\\[1em] = 7,500\Big[1 + \dfrac{8}{100}\Big]^2\\[1em] = 7,500\Big[1 + \dfrac{2}{25}\Big]^2\\[1em] = 7,500\Big[\dfrac{25}{25} + \dfrac{2}{25}\Big]^2\\[1em] = 7,500\Big[\dfrac{(25 + 2)}{25}\Big]^2\\[1em] = 7,500\Big[\dfrac{27}{25}\Big]^2\\[1em] = 7,500\Big[\dfrac{729}{625}\Big]^2\\[1em] = \Big[\dfrac{54,67,500}{625}\Big]^2\\[1em] = ₹ 8,748

And

C.I. = A - P=(8,7487,500)=1,248\text{C.I. = A - P}\\[1em] = ₹ (8,748 - 7,500)\\[1em] = ₹ 1,248

Difference between C.I. and S.I.

= ₹ (1,248 - 1,200)

= ₹ 48

The difference between C.I. and S.I. = ₹ 48.

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