KnowledgeBoat Logo
|

Chemistry

Calculate the following :

The volume at s.t.p. occupied by a gas 'Z' originally occupying 1.57 dm3 at 310.5 K and 75 cm. press. of Hg.

Gas Laws

40 Likes

Answer

Initial conditionsFinal conditions [S.t.p.]
P1 = Initial pressure of the gas = 75 cmP2 = Final pressure of the gas = 76 cm
V1 = Initial volume of the gas = 1.57 dm3V2 = Final volume of the gas = ?
T1 = Initial temperature of the gas = 310.5 KT2 = Final temperature of the gas = 273 K

By Gas Law:

P1×V1T1=P2×V2T2\dfrac{\text{P}1\times\text{V}1}{\text{T}1} = \dfrac{\text{P}2\times\text{V}2}{\text{T}2}

Substituting the values :

75×1.57310.5=76×V2273V2=75×1.57×273310.5×76V2=1.36 dm3\dfrac{75\times 1.57}{310.5} = \dfrac{76\times\text{\text{V}}2}{273} \\[1em] \text{V}2 =\dfrac{75\times 1.57 \times 273}{310.5\times 76} \\[1em] \text{V}_2 = 1.36 \text{ dm}^3

Therefore, final volume of the gas = 1.36 dm3

Answered By

23 Likes


Related Questions