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Chemistry

Calculate the number of moles of KClO3 that will be required to give 6 moles of oxygen.

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Answer

2KClO3 ⟶ 2KCl + 3O2

O2:KClO33:26:x\begin{matrix} \text{O}2 & : & \text{KClO}3 & \ 3 & : & 2 \ 6 & : & x \end{matrix}

23×6=xx=4 moles\dfrac{2}{3} \times 6 = x \\[0.5em] \Rightarrow x = 4 \text{ moles}

Hence, 4 moles of KClO3 are required to give 6 moles of oxygen.

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