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Chemistry

Calculate the temperature at which a gas A at 20°C having a volume of 500 cc. will occupy a volume of 250 cc.

Gas Laws

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Answer

V1 = Initial volume of the gas = 500 cc
T1 = Initial temperature of the gas = 20°C = 20 + 273 = 293 K

T2 = Final temperature of the gas = ?
V2 = Final volume of the gas = 250 cc

By Charles's Law:

V1T1=V2T2\dfrac{\text{V}1}{\text{T}1} = \dfrac{\text{V}2}{\text{T}2}

Substituting the values :

500293=250T2T2=2932V2=146.5 K\dfrac{500}{293} = \dfrac{250}{\text{T}2} \\[0.5em] \text{T}2 = \dfrac{293}{2} \\[0.5em] \text{V}_2 = 146.5\text{ K}

Final temperature in °C = 146.5 - 273 = -126.5°C

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