Mathematics
| Category | Wages in ₹ per day | No. of workers |
|---|---|---|
| A | 500 | 2 |
| B | 600 | 4 |
| C | 700 | 8 |
| D | 800 | 12 |
| E | 900 | 10 |
| F | 1000 | 6 |
| G | 1100 | 8 |
(i) Calculate done mean wages correct to the nearest rupees.
(ii) If the number of workers in each categories double what would be the new mean wage?
Measures of Central Tendency
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Answer
(i) We construct the following table:
| Category | Wages in ₹ per day (xi) | No. of workers (fi) | fixi |
|---|---|---|---|
| A | 500 | 2 | 1000 |
| B | 600 | 4 | 2400 |
| C | 700 | 8 | 5600 |
| D | 800 | 12 | 9600 |
| E | 900 | 10 | 9000 |
| F | 1000 | 6 | 6000 |
| G | 1100 | 8 | 8800 |
| Total | Σfi = 50 | Σfixi = 42400 |
Mean =
=
= 848.
Hence, the mean wage is ₹ 848.
(ii) If the number of workers in each category is doubled then total wage will also be doubled.
New total wage = 42400 × 2 = 84800 and number of workers = 50 × 2 = 100.
Mean =
=
= = 848.
Hence, the new mean wage is also ₹ 848.
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