Define a class to overload the method display() with the following variations:

1. void display() — To display the following pattern:

    0 1 0 1 0
    0 1 0 1 0
    0 1 0 1 0

2. int display(int x[]) — To return the smallest element of the array.

Example:

{6, 8, 4, 13, 2, 21}

Smallest element = 2

3. void display(double a, char b) — To calculate and display the area of circle if b is 'C' otherwise calculate and display the area of square if b is 'S'. For any other value of b print "Invalid operation".

Area of circle = πr²

Area of square = side²

public class KboatDisplay
{
    void display() {
        _______(1)_________
            _______(2)_________
                _______(3)_________
                    System.out.print("0  ");
                } else {
                    System.out.print("1  ");
                }
            }
            System.out.println();
        }
    }
    
    _______(4)_________ {
        int min = x[0];
        _______(5)_________
            _______(6)_________
                min = x[i];
            }
        }
        return min;
    }
    
    _______(7)_________ {
        _______(8)_________ {
            double area = Math.PI * a * a;
            System.out.println("Area of Circle: " + area);
        } _______(9)_________ {
            double area = a * a;
            System.out.println("Area of Square: " + area);
        } else {
            _______(10)_________
        }
    }
}

1. for (int i = 0; i < 3; i++) {
2. for (int j = 0; j < 5; j++) {
3. if (j % 2 == 0) {
4. int display(int x[])
5. for (int i = 1; i < x.length; i++) {
6. if (x[i] < min) {
7. void display(double a, char b)
8. if (b == 'C' || b == 'c')
9. else if (b == 'S' || b == 's')
10. System.out.println("Invalid operation");

Explanation

public class KboatDisplay
{
    void display() {
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 5; j++) {
                if (j % 2 == 0) {
                    System.out.print("0  ");
                } else {
                    System.out.print("1  ");
                }
            }
            System.out.println();
        }
    }
    
    int display(int x[]) {
        int min = x[0];
        for (int i = 1; i < x.length; i++) {
            if (x[i] < min) {
                min = x[i];
            }
        }
        return min;
    }
    
    void display(double a, char b) {
        if (b == 'C' || b == 'c') {
            double area = Math.PI * a * a;
            System.out.println("Area of Circle: " + area);
        } else if (b == 'S' || b == 's') {
            double area = a * a;
            System.out.println("Area of Square: " + area);
        } else {
            System.out.println("Invalid operation");
        }
    }
}

Variable Description Table

Method: void display()

Method: int display(int x[])

Method: void display(double a, char b)

Program Explanation

Let's take a closer look at this Java program to understand how it works:

void display() Method:

• This variation of the display() method is parameterless and is responsible for printing a specific pattern.
• The method uses nested for loops to achieve this pattern output. The outer loop runs three times (i from 0 to 2), which corresponds to the three lines of output.
• The inner loop runs five times (j from 0 to 4) on each iteration of the outer loop, printing either "0" or "1" followed by two spaces, depending on whether the current index j is even or odd.
• If the index j is even, "0 " is printed; if odd, "1 " is printed. This creates the alternating pattern "0 1 0 1 0" on each line.
• System.out.println() is used at the end of each iteration of the outer loop to move to the next line after completing a pattern line.

int display(int x[]) Method:

• This method takes an integer array as its parameter and returns the smallest element in the array.
• Initially, it assumes that the first element x[0] is the smallest (min = x[0]).
• It iterates over the array elements starting from the second element (i from 1 to x.length-1).
• For each element, it compares the current element x[i] with the current minimum min.
• If an element x[i] is smaller than the current minimum, min is updated to this element.
• At the end of the loop, min contains the smallest element of the array, which is then returned.

void display(double a, char b) Method:

• This method accepts two parameters: a double a, and a character b.
• It performs different calculations based on the value of the character b.
• If b is 'C' or 'c', the method calculates the area of a circle using the formula πa² (Math.PI * a * a) and prints it.
• If b is 'S' or 's', it calculates the area of a square using the formula a², and then prints the result.
• For any other character value of b, it prints "Invalid operation", indicating that the input character is not one of the expected options ('C' or 'S').

Output