Chemistry
Define the terms – (a) Relative atomic mass (b) Relative molecular mass. State why indirect methods are utilized to determine the absolute mass of an atom. Explain in brief the indirect method used.
Relative Atomic Mass
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Answer
(a) The number of times one atom of an element is heavier than 1⁄12th the mass of an atom of carbon [C12] is known as the Relative Atomic Mass [RAM] of the element.
(b) The number of times one molecule of the substance is heavier than 1⁄12th the mass of an atom of carbon [C12] is known as Relative Molecular Mass [RMM] of the element.
As atoms are extremely small and very light, hence cannot be weighed directly. So indirect methods are utilized to determine the absolute mass of an atom.
The relative mass of an atom or molecule is hence considered by considering a mass of a light atom and relating the mass of other atoms or molecules to it.
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Balance the following important equations :
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Pb(NO3)2 + NaCl ⟶ NaNO3 + PbCl2
FeSO4 + NaOH ⟶ Na2SO4 + Fe(OH)2
FeCl3 + NaOH ⟶ NaCl + Fe(OH)3
CuSO4 + NaOH ⟶ Na2SO4 + Cu(OH)2
FeCl3 + NH4OH ⟶ NH4Cl + Fe(OH)3
ZnO + NaOH ⟶ Na2ZnO2 + H2O
Pb(OH)2 + NaOH ⟶ Na2PbO2 + H2O
Al2O3.2H2O + NaOH ⟶ NaAlO2 + H2O
NaAlO2 + H2O ⟶ NaOH + Al(OH)3
Al(OH)3 ⟶ Al2O3 + H2O
ZnS + O2 ⟶ ZnO + SO2
Fe2O3 + Al ⟶ Al2O3 + Fe
Al + Cl2 ⟶ AlCl3
NaCl + H2SO4 ⟶ Na2SO4 + HCl
Fe + HCl ⟶ FeCl2 + H2
Na2CO3 + HCl ⟶ NaCl + H2O + CO2
Pb(NO3)2 + HCl ⟶ PbCl2 + HNO3
AgCl + NH4OH ⟶ Ag(NH3)2Cl + H2O
MnO2 + HCl ⟶ MnCl2 + H2O + Cl2
Pb3O4 + HCl ⟶ PbCl2 + H2O + Cl2
KMnO4 + HCl ⟶ KCl + MnCl2 + H2O + Cl2
K2Cr2O7 + HCl ⟶ KCl + CrCl3 + H2O + Cl2
NH4Cl + Ca(OH)2 ⟶ CaCl2 + H2O + NH3
(NH4)2SO4 + NaOH ⟶ Na2SO4 + H2O + NH3
Mg3N2 + H2O ⟶ Mg(OH)2 + NH3
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NH4OH + H2SO4 ⟶ (NH4)2SO4 + H2O
NH3 + CuO ⟶ Cu + H2O + N2
NH3 + Cl2 ⟶ HCl + NCl3 [nitrogen trichloride]
HNO3 ⟶ H2O + NO2 + O2
Ca(HCO3)2 + HNO3 ⟶ Ca(NO3)2 + H2O + CO2
C + HNO3 [conc.] ⟶ CO2 + H2O + NO2
S + HNO3 [conc.] ⟶ H2SO4 + H2O + NO2
Cu + HNO3 [conc.] ⟶ Cu(NO3)2 + H2O + NO2
C + H2SO4 [conc.] ⟶ CO2 + H2O + SO2
S + H2SO4 [conc.] ⟶ SO2 + H2O
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- Reaction of excess ammonia with chlorine – Ammonia as a reducing agent
(a) Ammonia first reacts with chlorine to give hydrogen chloride and nitrogen.
(b) Hydrogen chloride then further reacts with excess ammonia to give ammonium chloride. - Oxidation of Lead [II] Sulphide by Ozone
(a) Ozone first decomposes to give molecular oxygen & nascent oxygen.
(b) Nascent oxygen then oxidizes lead [II] sulphide to lead [II] sulphate.
- Reaction of excess ammonia with chlorine – Ammonia as a reducing agent
Calculate relative molecular mass of
(a) ZnCO3
(b) CaSO4[Zn = 65, S = 32, O = 16, Ca = 40, C = 12]
Calculate the percentage composition of
(a) calcium chloride
(b) calcium nitrate[Ca = 40 , Cl = 35.5 , N = 14 , O = 16]