Chemistry
The below diagram represents the electrolysis of acidulated water. The reaction occurring at the anode is:
- H2SO4 ⟶ 2H+ + SO42-
- H2O ⟶ H+ + OH-
- H+ + e- ⟶ H, 2[H] + 2[H] ⟶ H2
- OH- - e- → OH, [4OH] ⟶ 2H2O + O2
Electrolysis
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Answer
OH- - e- → OH, [4OH] ⟶ 2H2O + O2
Reason — OH- migrates to the anode. OH- being lower in the electro-chemical series is discharged preferentially. OH- loses one electron to the anode and becomes neutral OH.
OH- - e- → OH
The combination of OH forms water with the liberation of oxygen, which is given off at the anode.
[4OH] ⟶ 2H2O + O2
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