Evaluate:
(a2b+2ba)\Big(\dfrac{a}{2b} +\dfrac{2b}{a}\Big)(2ba+a2b) (a2b−2ba)\Big(\dfrac{a}{2b} -\dfrac{2b}{a}\Big)(2ba−a2b)
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Using the formula
[∵ (x + y)(x - y) = x2 - y2]
= (a2b)2−(2ba)2\Big(\dfrac{a}{2b}\Big)^2 - \Big(\dfrac{2b}{a}\Big)^2(2ba)2−(a2b)2
= (a24b2)−(4b2a2)\Big(\dfrac{a^2}{4b^2}\Big) - \Big(\dfrac{4b^2}{a^2}\Big)(4b2a2)−(a24b2)
Hence, (a2b+2ba)\Big(\dfrac{a}{2b} +\dfrac{2b}{a}\Big)(2ba+a2b) (a2b−2ba)\Big(\dfrac{a}{2b} -\dfrac{2b}{a}\Big)(2ba−a2b) = (a24b2)−(4b2a2)\Big(\dfrac{a^2}{4b^2}\Big) - \Big(\dfrac{4b^2}{a^2}\Big)(4b2a2)−(a24b2)
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