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Mathematics

Find the amount and the compound interest on ₹ 64,000 for 1121\dfrac{1}{2} year at 15% per annum, compounded half-yearly.

Compound Interest

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Answer

Given,

Rate = 15%

Half yearly rate (R) = Rate2=15%2\dfrac{\text{Rate}}{2} = \dfrac{15\%}{2} = 7.5%

Time = 1121\dfrac{1}{2} year = 32×2\dfrac{3}{2} \times 2 = 3 half-year.

For first half year :

P = ₹ 64,000

T = 1 half year

I = P×R×T100\dfrac{P \times R \times T}{100}

=64,000×7.5×1100= \dfrac{64,000 \times 7.5 \times 1}{100} = ₹ 4,800

Amount = P + I = ₹ 64,000 + ₹ 4,800 = ₹ 68,800

For second half year :

P = ₹ 68,800

Half yearly rate (R) = 7.5%

T = 1 half year

I = P×R×T100\dfrac{P \times R \times T}{100}

=68800×7.5×1100= \dfrac{68800 \times 7.5 \times 1}{100} = ₹ 5,160.

Amount = P + I = ₹ 68,800 + ₹ 5,160 = ₹ 73,960.

For third half year :

P = ₹ 73,960

Half yearly rate (R) = 7.5%

T = 1 year

I = P×R×T100\dfrac{P \times R \times T}{100}

=73960×7.5×1100= \dfrac{73960 \times 7.5 \times 1}{100} = ₹ 5,547.

Amount = P + I = ₹ 73,960 + ₹ 5,547 = ₹ 79,507.

Compound interest = Final amount - Initial principal

= ₹ 79,507 - ₹ 64,000 = ₹ 15,507.

Hence, final amount = ₹ 79,507 and compound interest = ₹ 15,507.

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