KnowledgeBoat Logo
|

Mathematics

Find the coefficient of x2 in the expansion of

(x2 + x + 1)2 + (x2 - x + 1)2.

Expansions

25 Likes

Answer

The above equation can be written as,

(x2+x+1)2+(x2x+1)2=(x2+1)+x2+(x2+1)x2=2(x2+1)2+x2=2(x2)2+1+2x2+x2=2x4+3x2+1=2x4+6x2+2.(x^2 + x + 1)^2 + (x^2 - x + 1)^2 = {(x^2 + 1) + x}^2 + {(x^2 + 1) - x}^2 \\[1em] = 2{(x^2 + 1)^2 + x^2} \\[1em] = 2{(x^2)^2 + 1 + 2x^2 + x^2} \\[1em] = 2{x^4 + 3x^2 + 1} \\[1em] = 2x^4 + 6x^2 + 2.

Hence, coefficient of x2 = 6.

Answered By

16 Likes


Related Questions