Give balanced chemical equation for the following.

(a) Preparation of ethyne from (ethylene dibromide) 1, 2-di bromoethane.

(b) Ethanoic acid from ethanol.

(c) Sodium acetate from acetic acid.

(a) Ethyne from (ethylene dibromide) 1, 2-di bromoethane.

$\underset{\text{ ethylene dibromide}}{\text{C}$2\text{H}4\text{Br}2} + \underset{\text{ alcoholic KOH}}{\text{2KOH [aq.]}} \xrightarrow{\text{boil}} \underset{\text{ Ethene [ethylene]} }{\text{C}2\text{H}2} + \text{2KBr} +\text{2H}2\text{O}

(b) Ethanoic acid from ethanol.

$\underset{ \text{ethanol}}{\text{C}$2\text{H}5\text{OH}} \xrightarrow[\underset{\text{[acidified]}}{\text{K}2\text{Cr}2\text{O}7}]{\text{[O]}} \underset{\text{ethanal}}{\text{CH}3\text{CHO}} \xrightarrow[\underset{\text{[acidified]}}{\text{K}2\text{Cr}2\text{O}7}]{\text{[O]}} \underset{ \text{ethanoic acid} }{\text{CH}3\text{COOH}}

(c) Sodium acetate from acetic acid.

CH₃COOH + NaOH ⟶ CH₃COONa + H₂O